view example/word_count/ppe/Print.cc @ 666:4615489c5faa

simplify word_count
author Shinji KONO <kono@ie.u-ryukyu.ac.jp>
date Thu, 03 Dec 2009 02:11:31 +0900
parents 60aa3f241b10
children ccf78a465459
line wrap: on
line source

#include <stdio.h>
#include <string.h>
#include "Print.h"
#include "Func.h"

/* これは必須 */
SchedDefineTask(Print);

static int
run(SchedTask *s, void *rbuf, void *wbuf)
{
    unsigned long long *idata = (unsigned long long*)s->get_input(rbuf, 0);
    long task_num = (long)s->get_param(0);
    long status_num = (long)s->get_param(1);
    unsigned long long word_data[task_num];

    s->printf("start sum\n");

    for (int i = 0; i < status_num; i++) {
	word_data[i] = 0;
    }

    for (int i = 0; i < task_num*status_num; i += status_num) {
	for (int j = 0; j < status_num; j++) {
	    word_data[j] += idata[i+j];
	}
    }

    for (int i = status_num; i > 0; i--) {
	s->printf("%llu ",word_data[i-1]);
    }

    s->printf("\n");


    return 0;
}