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annotate gcc/testsuite/gcc.dg/loop-versioning-13.c @ 145:1830386684a0

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gcc-9.2.0
author anatofuz
date Thu, 13 Feb 2020 11:34:05 +0900
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145
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1 /* { dg-options "-O3 -fdump-tree-lversion-details" } */
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2
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3 /* Test that we do version for a step of 1 when that would lead the
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4 iterations to access consecutive groups. */
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5
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6 void
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7 f1 (unsigned short *x, int stepx, int n)
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8 {
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9 for (int i = 0; i < n; ++i)
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10 {
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11 x[i * stepx * 2] = 100;
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12 x[i * stepx * 2 + 1] = 99;
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13 }
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14 }
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15
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16 void
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17 f2 (unsigned short *x, int stepx, int n)
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18 {
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19 for (int i = 0; i < n; i += stepx * 2)
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20 {
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21 x[i] = 100;
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22 x[i + 1] = 99;
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23 }
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24 }
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25
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26 void
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27 f3 (unsigned short *x, int stepx, int n)
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28 {
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29 for (int i = 0; i < n; ++i)
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30 {
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31 x[i * stepx * 2 - 16] = 100;
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32 x[i * stepx * 2 - 15] = 99;
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33 }
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34 }
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35
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36 void
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37 f4 (unsigned short *x, int stepx, int n)
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38 {
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39 for (int i = 0; i < n; i += stepx * 2)
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40 {
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41 x[i - 16] = 100;
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42 x[i - 15] = 99;
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43 }
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44 }
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45
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46 void
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47 f5 (unsigned short *x, int stepx, int n)
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48 {
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49 for (unsigned short *y = x; y < x + n; y += stepx * 2)
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50 {
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51 y[0] = 100;
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52 y[1] = 99;
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53 }
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54 }
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55
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56 unsigned short x[1000];
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57
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58 void
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59 g1 (int stepx, int n)
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60 {
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61 for (int i = 0; i < n; ++i)
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62 {
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63 x[i * stepx * 2] = 100;
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64 x[i * stepx * 2 + 1] = 99;
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65 }
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66 }
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67
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68 void
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69 g2 (int stepx, int n)
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70 {
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71 for (int i = 0; i < n; i += stepx * 2)
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72 {
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73 x[i] = 100;
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74 x[i + 1] = 99;
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75 }
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76 }
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77
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78 void
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79 g3 (int stepx, int n)
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80 {
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81 for (int i = 0; i < n; ++i)
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82 {
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83 x[i * stepx * 2 - 16] = 100;
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84 x[i * stepx * 2 - 15] = 99;
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85 }
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86 }
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87
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88 void
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89 g4 (int stepx, int n)
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90 {
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91 for (int i = 0; i < n; i += stepx * 2)
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92 {
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93 x[i - 16] = 100;
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94 x[i - 15] = 99;
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95 }
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96 }
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97
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98 void
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99 g5 (int stepx, int n)
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100 {
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101 for (unsigned short *y = x; y < x + n; y += stepx * 2)
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102 {
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103 y[0] = 100;
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104 y[1] = 99;
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105 }
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106 }
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107
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108 /* { dg-final { scan-tree-dump-times {want to version containing loop} 10 "lversion" } } */
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109 /* { dg-final { scan-tree-dump-times {versioned this loop} 10 "lversion" } } */